x+y=-1 z+x=0 y+z=1x+y=-1 z+x=0 y+z=1
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x+y=-1z+x=0y+z=1x+y=-1z+x=0y+z=1x+y=-1z+x=0y+z=1x+y=-1z+x=0y+z=1x+y=-1z+x=0y+z=1x+y=-1z+x=0y+z=1x+y=
x+y=-1 z+x=0 y+z=1x+y=-1 z+x=0 y+z=1
x+y=-1 z+x=0 y+z=1
x+y=-1
z+x=0
y+z=1
x+y=-1 z+x=0 y+z=1x+y=-1 z+x=0 y+z=1
x+y=-1 (1)
z+x=0 (2)
y+z=1 (3)
(1)-(2)得 y-z=-1 (4)
(4)+(3)得 2y=0
y=0
代入(1)得 x=-1
代入(3)得 z=1
X+2Y+Z=0; zY+Z=Z; Y=0;Z=1;X=-1
y=1-z
x+1-z=-1
z=x+2
2x+2=0
x=-1
y=0
z=1
从第二条式可得
Z=-X
-Z=X
X+Y=-1
Y+Z=1
所以
Y-Z=-1
Y+Z=1
解方程 可得
Y=0
Z=1
X=-1
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