[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²] 其中x=1,y=2数学:[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²] 其中x=1,y=2
来源:学生作业帮助网 编辑:六六作业网 时间:2024/08/27 22:19:18
[2x²-(x+y)(x-y)][(-x-y)(y-x)+2y²]其中x=1,y=2数学:[2x²-(x+y)(x-y)][(-x-y)(y-x)+2y²]其中
[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²] 其中x=1,y=2数学:[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²] 其中x=1,y=2
[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²] 其中x=1,y=2
数学:[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²] 其中x=1,y=2
[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²] 其中x=1,y=2数学:[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²] 其中x=1,y=2
[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²]
=[2x²-(x²-y²)][(x+y)(x-y)+2y²]
=(2x²-x²+y²)(x²-y²+2y²)
=(x²+y²)²
=(1²+2²)²
=5²
=25
=(x^2+y^2)^2=25
[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²]
=[2x²-(x²-y²)][(x+y)(x-y)+2y²]
=(2x²-x²+y²)(x²-y²+2y²)
=(x²+y²)²
=(1²+2²)²
=5²
=25
平方差公式x²-y²=(x+y)(x-y)