怎么把x²-xy+y²分之x²+2xy-3y³因式分解啊,应该是x²-xy+y²分之x²+2xy-3y²

怎么把x²-xy+y²分之x²+2xy-3y³因式分解啊,应该是x²-xy+y²分之x²+2xy-3y²
怎么把x²-xy+y²分之x²+2xy-3y³因式分解啊,
应该是x²-xy+y²分之x²+2xy-3y²

怎么把x²-xy+y²分之x²+2xy-3y³因式分解啊,应该是x²-xy+y²分之x²+2xy-3y²
再改一下吧
x²- 2 xy+y²分之x²+2xy-3y²
=(x+3y)(x-y)/(x-y)²
=(x+3y)/(x-y)

你确定题打对了？