设A=2x^2-3xy+y^3-x+2y,B=4x^2-6xy+2y^2+3x-y,若x-2a差的绝对值+(y+3)^2=0且B-2A=a,求A的值

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设A=2x^2-3xy+y^3-x+2y,B=4x^2-6xy+2y^2+3x-y,若x-2a差的绝对值+(y+3)^2=0且B-2A=a,求A的值设A=2x^2-3xy+y^3-x+2y,B=4x^

设A=2x^2-3xy+y^3-x+2y,B=4x^2-6xy+2y^2+3x-y,若x-2a差的绝对值+(y+3)^2=0且B-2A=a,求A的值
设A=2x^2-3xy+y^3-x+2y,B=4x^2-6xy+2y^2+3x-y,若x-2a差的绝对值+(y+3)^2=0且B-2A=a,求A的值

设A=2x^2-3xy+y^3-x+2y,B=4x^2-6xy+2y^2+3x-y,若x-2a差的绝对值+(y+3)^2=0且B-2A=a,求A的值
由题意可知 a = -2y^3 + 2y^2 + x + 3y
所以 x - 2a = x + 4y^3 - 4y^2 - 4x - 6y
因为一个绝对值加一个平方是 0,所以这两项均为 0
即 (y + 3)^2 = 0,y = -3
带入 x - 2a = 0 中,得:
x + 4×(-3)^3 - 4×(-3)^2 - 4x - 6×(-3)
= -3x - 126 = 0
x = -42
带入 A 中,得:A = 3159