x+y=-3,xy=-2,求x³y²+x²y³的值

x+y=-3,xy=-2,求x³y²+x²y³的值
x+y=-3,xy=-2,求x³y²+x²y³的值

x+y=-3,xy=-2,求x³y²+x²y³的值
答：
x+y=-3,xy=-2
x³y²+x²y³
=x²y²(x+y)
=(-2)*(-2)*(-3)
=-12

x+y=-3,xy=-2,求x³y²+x²y³的值
x³y²+x²y³
= x²y² (x+y )
= (xy) ² (x+y)
= (-2 ) ² x (-3)
= 4 x (-3)
= -12
施主，我...

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x+y=-3,xy=-2,求x³y²+x²y³的值
x³y²+x²y³
= x²y² (x+y )
= (xy) ² (x+y)
= (-2 ) ² x (-3)
= 4 x (-3)
= -12
施主，我看你骨骼清奇，
器宇轩昂,且有慧根,
乃是万中无一的武林奇才.
潜心修习,将来必成大器，
鄙人有个小小的考验请点击在下答案旁的
"选为满意答案"

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x³y²+x²y³
=(xy)²·x+(xy)²·y
=（xy）²（x+y）
因为
x+y=-3,xy=-2,
所以原式等于-12