满足x²—x+1=0求(x-1)³+(x-1)²+(x-1)的值
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满足x²—x+1=0求(x-1)³+(x-1)²+(x-1)的值满足x²—x+1=0求(x-1)³+(x-1)²+(x-1)的值满足x
满足x²—x+1=0求(x-1)³+(x-1)²+(x-1)的值
满足x²—x+1=0求(x-1)³+(x-1)²+(x-1)的值
满足x²—x+1=0求(x-1)³+(x-1)²+(x-1)的值
原式=(x-1)[(x-1)²+(x-1)+1]
=(x-1)(x²-2x+1+x-1+1)
=(x-1)(x²-x+1)
=(x-1)*0
=0