已知α为锐角,且sinα-cosα=1/5,则tanα-1/(tanα)=

已知α为锐角,且sinα-cosα=1/5,则tanα-1/(tanα)=
已知α为锐角,且sinα-cosα=1/5,则tanα-1/(tanα)=

已知α为锐角,且sinα-cosα=1/5,则tanα-1/(tanα)=
根据sina^2+cosa^2=1可以推出sina=4/5 cosa=3/5
所以tana=4/3
tanα-1/(tanα)=7/12