已知函数f(x)=ln(x+1)+ax若存在x∈[1,2],使不等式f'(x)≥2x成立,求a范围等差数列{An}的前n项和为Sn,已知A(m-1)+A(m+1)-A(m)²=0 S(2m-1)=38,（括号内的数位于下标）则m=（）设等比数列{An}的前n项和为Sn,若A

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已知函数f(x)=ln(x+1)+ax若存在x∈[1,2],使不等式f''(x)≥2x成立,求a范围等差数列{An}的前n项和为Sn,已知A(m-1)+A(m+1)-A(m)²=0S(2m-1

已知函数f(x)=ln(x+1)+ax若存在x∈[1,2],使不等式f'(x)≥2x成立,求a范围等差数列{An}的前n项和为Sn,已知A(m-1)+A(m+1)-A(m)²=0 S(2m-1)=38,（括号内的数位于下标）则m=（）设等比数列{An}的前n项和为Sn,若A
已知函数f(x)=ln(x+1)+ax若存在x∈[1,2],使不等式f'(x)≥2x成立,求a范围
等差数列{An}的前n项和为Sn,已知A(m-1)+A(m+1)-A(m)²=0
S(2m-1)=38,（括号内的数位于下标）则m=（）
设等比数列{An}的前n项和为Sn,若A1=1,S6=4*S3,则A4=（）
设函数f(x)=3x^2+a/x^3(x∈(o,+∞))求正数a的取值范围,使对于任意x∈(0,+∞)都有f(x)>=20.
已知函数f（x）＝（ax＋1）×a的（－x）次幂,a＞0且a≠1
（1） 讨论f（x）的单调性,并求出极值x0
（2）若（1）中的x0＝g（a）在（1,e〕上的最小值

已知函数f(x)=ln(x+1)+ax若存在x∈[1,2],使不等式f'(x)≥2x成立,求a范围等差数列{An}的前n项和为Sn,已知A(m-1)+A(m+1)-A(m)²=0 S(2m-1)=38,（括号内的数位于下标）则m=（）设等比数列{An}的前n项和为Sn,若A
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最后一体的题目看的不是特明白，不太清楚你写的啥

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