设lim((x^2+1)/(x+1) -ax-b)=0,求a,b.x趋向无穷大
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 18:50:47
设lim((x^2+1)/(x+1)-ax-b)=0,求a,b.x趋向无穷大设lim((x^2+1)/(x+1)-ax-b)=0,求a,b.x趋向无穷大设lim((x^2+1)/(x+1)-ax-b)
设lim((x^2+1)/(x+1) -ax-b)=0,求a,b.x趋向无穷大
设lim((x^2+1)/(x+1) -ax-b)=0,求a,b.x趋向无穷大
设lim((x^2+1)/(x+1) -ax-b)=0,求a,b.x趋向无穷大
lim[(x^2+1)/(x+1) -ax-b]
=lim[(x+1)-2x/(x+1)-ax-b]
=lim[(1-a)x-(1+b)]
=0
1-a=0 a=1
1+b=0 b=-1
用Mathematic输入limt[(x^2+1)/(x+1) -ax-b),x->infinity]
得1-a,因1-a=0,所以a=1
输入limt[(x^2+1)/(x+1) -x-b),x->infinity]
得-1-b,因-1-b=0,所以b=-1
设函数f(x)=3x^2+2x-lim x→1f(x),则lim x→1f(x)=?
设函数f x=e^2x-2x,lim f'(x)/e^x -1等于 ,x→0
lim(1-x)^(2/x) x->0
设f(x)=e^(-x),则lim(x趋向于0) (f ' (1-2x)-f '(1)) / x
设f'(x)=2,求极限lim(x~0)[f(1-x)-f(1+x)]/x
设函数f(x)连续,lim((f(x)/x)-1/x-(sinx/x^2))=2,f(0)=?
设函数f(x)连续,lim((f(x)/x)-1/x-(sinx/x^2))=2,f(0)=?
12、设lim(x→0) (1-mx)^1/x =e^2,则m=?
设lim[(x^2+2x+3)^1/2-ax]=b,求a,b
利用函数极限求数列极限(例题)设函数f(x)=(tanx/x)^((1/(x^2))于是x趋于0 lim f(x) =x趋于0 lim(tan/x)^(1/(x^2))=e^lim x趋于0 ln (tanx/x)/(x^2)=e ^lim x趋于0 ((tan/x)-1)/(x^2)=e^lim x趋于0 (tanx-x)/(x^3)=e^1/3 lim x趋于0 (
设f(x)=lim(x-->无穷)(n-1)x/nx^2+1,f(X)的间断点是?
设lim(x>0) f(x)/x=1,求lim(x->0) {[1+f(x)]^1/2 -1} /设lim(x>0) f(x)/x=1,求lim(x->0) {[1+f(x)]^1/2 -1} /x=
极限:lim(x->2)1/(x-2)
lim(1-(5/x))^x-2
lim(x+e^2x)^(1/sinx)
高数极限习题解答一、lim(x->0)sin3x/sin2x二、lim(x->0)√1+x² -1/sinx三、设函数f(x)=(X-2)2,X >1X,-1《x《1X+1,X
设f(x)=1/(1+e^(1/x)) 求 lim f(x) x->0
设f(x)是多项式,且lim(x→∞)[f(x)-x^3]/x^2=2,且lim(x→0)f(x)/x=1,求f(x)