【1/(x+1)+1/(x-1)】(x2-1) 分式化简.
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 02:52:33
【1/(x+1)+1/(x-1)】(x2-1)分式化简.【1/(x+1)+1/(x-1)】(x2-1)分式化简.【1/(x+1)+1/(x-1)】(x2-1)分式化简.【1/(x+1)+1/(x-1)
【1/(x+1)+1/(x-1)】(x2-1) 分式化简.
【1/(x+1)+1/(x-1)】(x2-1) 分式化简.
【1/(x+1)+1/(x-1)】(x2-1) 分式化简.
【1/(x+1)+1/(x-1)】(x²-1)
=【1/(x+1)】*(x²-1)+【1/(x-1)】*(x²-1)
=x-1 + x+1
=2x
(x2+4x)/(x-1)
7/x2+x+1/x2-x=6/x2-1
化简x/x2+x除以x2+x-2/x2-1+x+1/x+2
lim(根号X2+X-根号X2+1)
计算(x3+x2+x+2)/(x2+1)
6x2-[-3x2-(x-1)] 化简
x2-1/x2-5x+6
x2次方+x/x2次方-1,分式
约分 1-x2/x2-3x-4
(1-x2)(x2-4x+5)
不等式(x2-4x-5)(x2+1)
3/x2 -3x+2-1/x-2=1/x2 -x+4/x2 -2x
通分 3x/x2-2x,2x+1/4-x2,3/2x2+4x
化简x(x2-3)+x2(x-3)-3x(x2-x-1)
化简x-1分之x+1-x2-1分之x2-2x÷x2-x-2/x2+2x+1
x2-3x+1=0 x2/(x4-x2+1)
x2-5x+1=0则x2+x2/1
计算:x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2