求证sin(2A+B)/sinA-2cos(A+B)=sinB/sinA

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求证sin(2A+B)/sinA-2cos(A+B)=sinB/sinA求证sin(2A+B)/sinA-2cos(A+B)=sinB/sinA求证sin(2A+B)/sinA-2cos(A+B)=s

求证sin(2A+B)/sinA-2cos(A+B)=sinB/sinA
求证sin(2A+B)/sinA-2cos(A+B)=sinB/sinA

求证sin(2A+B)/sinA-2cos(A+B)=sinB/sinA
sin(2a+b)/sina-2cos(a+b)=sinb/sina ==>左边=[sin(2a+b)-2cos(a+b)sina]/sina =[sina*cos(a+b)+sin(a+b)*cosa-2cos(a+b)sina]/sina =[sin(a+b)*cosa-cos(a+b)sina]/sina =sin(a+b-a)/sina=sinb/sina=右边