已知x+y=6.xy=7.求(3x+y)^2+(x+3y)^2的值

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/28 14:47:52
已知x+y=6.xy=7.求(3x+y)^2+(x+3y)^2的值已知x+y=6.xy=7.求(3x+y)^2+(x+3y)^2的值已知x+y=6.xy=7.求(3x+y)^2+(x+3y)^2的值(

已知x+y=6.xy=7.求(3x+y)^2+(x+3y)^2的值
已知x+y=6.xy=7.求(3x+y)^2+(x+3y)^2的值

已知x+y=6.xy=7.求(3x+y)^2+(x+3y)^2的值
(3x+y)^2+(x+3y)^2
=9x^2+6xy+y^2+x^2+6xy+9y^2
=10x^2+10y^2+12xy
=10(x^2+y^2)+12xy
=10(x^2+y^2+2xy)+12xy-10*2xy
=10(x+y)^2-8xy
=10*6^2-8*7
=360-56
=304

x²+y²=(x+y)²-2xy=22
(3x+y)^2+(x+3y)^2
= 9x²+6xy+y² + x²+6xy+9y²
=10(x²+y²)+12xy
=220+84=304

(x+y)^2=36
X^2+Y^2+2XY=36
2XY=14
X^2+Y^2=22
X^2+Y^2-2XY=22-14=8
(X-Y)^2=8
X-Y=2*2^0.5(二根号二)
因为X+Y=6
所以X=3+2^0.5
y=3-2^0.5
最后带进去算吧。。。

等下