1-(2-3)-(4-5)-(6-7)-……-(98-99)=
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1-(2-3)-(4-5)-(6-7)-……-(98-99)=1-(2-3)-(4-5)-(6-7)-……-(98-99)=1-(2-3)-(4-5)-(6-7)-……-(98-99)=50—4950
1-(2-3)-(4-5)-(6-7)-……-(98-99)=
1-(2-3)-(4-5)-(6-7)-……-(98-99)=
1-(2-3)-(4-5)-(6-7)-……-(98-99)=
50
—4950
50
=1-2+3-4+5-6+7-.....-98+99
=1+1+1+.......+1
=1×50
=50
1+49*1=50
1
50
50,绝对正确,其实是50个1相加