高数,不定积分,
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高数,不定积分,高数,不定积分, 高数,不定积分,要倒过来推：∫dx/(x^2+1)=x/(x^2+1)-∫xd(1/(x^2+1))=x/(x^2+1)+2∫x^2dx/(x^2+1)=x
高数,不定积分,
高数,不定积分,
高数,不定积分,
要倒过来推：
∫dx/(x^2+1)=x/(x^2+1)-∫xd(1/(x^2+1))
=x/(x^2+1)+2∫x^2dx/(x^2+1)
=x/(x^2+1)+2∫(x^2+1-1)dx/(x^2+1)^2
=x/(x^2+1)+2∫dx/(x^2+1)-2∫dx/(x^2+1)^2
所以∫dx/(x^2+1)^2=x/(2(x^2+1))+1/2*∫dx/(x^2+1)