[（4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3）]

来源：学生作业帮助网编辑：六六作业网时间：2024/12/19 14:39:32

[（4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3）][（4a²-4a)/(a²2a+1)]÷[a+1/(

[（4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3）]
[（4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3）]

[（4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3）]
原式=(4a(a-1)/2aaa+1)x（(a+1)(a-1)/4a）x（1/3(a+1)）
=(aa+1+2a)/(6aaa+3)