1/2[1-3/2y(y-3/8)]=y+5/6,用因式分解法解打错了是1/2[1-3/2y(y-8/3)]=y+5/6
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1/2[1-3/2y(y-3/8)]=y+5/6,用因式分解法解打错了是1/2[1-3/2y(y-8/3)]=y+5/61/2[1-3/2y(y-3/8)]=y+5/6,用因式分解法解打错了是1/2[
1/2[1-3/2y(y-3/8)]=y+5/6,用因式分解法解打错了是1/2[1-3/2y(y-8/3)]=y+5/6
1/2[1-3/2y(y-3/8)]=y+5/6,用因式分解法解
打错了是
1/2[1-3/2y(y-8/3)]=y+5/6
1/2[1-3/2y(y-3/8)]=y+5/6,用因式分解法解打错了是1/2[1-3/2y(y-8/3)]=y+5/6
1/2[1-3/2y(y-8/3)]=y+5/6
1-3/2 y﹙y-8/3﹚=2y+5/3
3/2 y﹙y-8/3﹚+2y+2/3=0
3/2 y²-2y+2/3=0
9y²-12y+4=0
﹙3y-2﹚²=0
y1=y2=2/3.
y (3y^2+8y-3)-6y(3y+2y-1)+9y
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
2(y-4)(3y+2)-5(-3y+7)(y+1),其中y=-1
(y-4)(3y+2)-(3y-7)(2y+1),其中y=4/3
解方程:3y^2-(2y+1)(y-1)=(y-5)(y+1)
解方程3y^2-(2y+1)(y-2)=(y-5)(y-1)
解方程:3y²-(2y+1)(y-2)=(y-5)(y+1)
解分式方程(y+3)/(y^2+y)-1/(1-y)=4/y要过程
Y(Y-1)-(y-2)*(y+3)=2 Y的解是多少?
通分 y+3/y*y-6y+9,1/2y+6,y-1/y*y-9
急,看不懂问我(y+3)^2/8-y=(y+3)/4-(y-1)/2
[T,Y]=ode45(@rigid,[0 1],[rand(15,1)]);plot(T,Y(:,1),'-',T,Y(:,2),'-.',T,Y(:,3),'.',T,Y(:,4),'-',T,Y(:,5),'-.',T,Y(:,6),'.',T,Y(:,7),'-',T,Y(:,8),'-.',T,Y(:,9),'.',T,Y(:,10),'-',T,Y(:,11),'-.',T,Y(:,12),'-.',T,Y(:,13),'.',T,Y(:,14),'-',T,Y(:,15),'.')
y-(y-1)/2=1-(2y-3)/5
2(y-1)=2y-3(y+1)
解方程3y(y-1)=2(1-y)
y-y-1/2=3-y+2/5