计算(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^6)(1+1/2^8)+1/2^15

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/27 19:57:28
计算(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^6)(1+1/2^8)+1/2^15计算(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^6)(1+1/2^8)+1/

计算(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^6)(1+1/2^8)+1/2^15
计算(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^6)(1+1/2^8)+1/2^15

计算(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^6)(1+1/2^8)+1/2^15
您好:
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^6)(1+1/2^8)+1/2^15
=2*(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^6)(1+1/2^8)+1/2^15
=2*(1-1/2^2)(1+1/2^2)(1+1/2^4)(1+1/2^6)(1+1/2^8)+1/2^15
=...
=2*(1-1/2^16)+1/2^15
=2-1/2^15+1/2^15
=2


如果本题有什么不明白可以追问,如果满意记得采纳
如果有其他问题请另发或点击向我求助,答题不易,请谅解,谢谢.
祝学习进步!

(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
=(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)/(1-1/2)+1/2^15
=(1-1/2^2)(1+1/2^2)(1+1/2^4)(1+1/2^8)*2+1/2^15
=(1-1/2^4)(1+1/2^4)(1+1/2^8)*2+1/2^15
=(1-1/2^8)(1+1/2^8)*2+1/2^15
=(1-1/2^16)*2+1/2^15
=2-1/2^15+1/2^15
=2

在 最前面 乘 (1-1/2) 最后 再 乘 2