化简；[x+3/x+2]+[2-x/x平方-4]的值

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化简；[x+3/x+2]+[2-x/x平方-4]的值化简；[x+3/x+2]+[2-x/x平方-4]的值化简；[x+3/x+2]+[2-x/x平方-4]的值原式=(x+3)/(x+2)-(x-2)/(

化简；[x+3/x+2]+[2-x/x平方-4]的值
化简；[x+3/x+2]+[2-x/x平方-4]的值

化简；[x+3/x+2]+[2-x/x平方-4]的值
原式=(x+3)/(x+2)-(x-2)/(x+2)(x-2)
=(x+3)/(x+2)-1/(x+2)
=(x+3-1)/(x+2)
=(x+2)/(x+2)
=1

解答;
[(x+3)/(x+2)]+[(2-x)/(x平方-4)]=[(x+3)/(x+2)]-(x-2)/[(x+2)(x-2)
=(x+3)/(x+2)-1/(x+2)=(x+3-1)/(x=2）=（x=2)/(x+2)=1

X^2-4=(X-2)(X+2)
所以(2-X)/(X^2-2)=-1/（X+2）
[(X+3)/(X+2)]-[1/(X+2)]=(X+2)/(X+2)=1