2x-y=7,x=2y+5z=1,3x-7y+z=4
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2x-y=7,x=2y+5z=1,3x-7y+z=42x-y=7,x=2y+5z=1,3x-7y+z=42x-y=7,x=2y+5z=1,3x-7y+z=4由2式得x=1,再代入1式得y=-5,把x=
2x-y=7,x=2y+5z=1,3x-7y+z=4
2x-y=7,x=2y+5z=1,3x-7y+z=4
2x-y=7,x=2y+5z=1,3x-7y+z=4
由2式得x=1,再代入1式得y=-5,把x=1,y=-5代入3式得z=-34
x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2
{5x-3y+z=2{5x+2y-4z=3{-5x+y-z=2 {x-y-z=-1{3x+5y+7z{4x-y+2x=-1
{x+y+z=1 {x+3y+7z=-1 {x+5y+8z=2
{x+y+z=1 {x+3y+7z=2 {x+5y+19z=4
1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=?
三元一次方程 X-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 X=?Y=?Z=?
x/2=y/3=z/5 x+3y-z/x-3y+z
x+y+z=1 x+3y+7z=-1 x+5y+8=2题错了 x+y+z=1 x+3y+7z=-1 x+5y+8z=2
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..1.x+y+z=26,2.4y+3z=7,y-z=1,3x+2z=17,x+2y-z=18 9x-7y=173.x-7y+3z=17 4.2x+4y+3z=95x-6y-z=24 3x-2y+5z=113x+7y-2z=1 5x-6y+7z=131.x+y+z=26,y-z=1x+2y-z=18 2.4y+3z=7,3x+2z=11,9x-7y=17 3.x-7y+3z=17 5x-6y-z=24 3x+7y-2z=14.2x+4y+3z=93x-2y+5z=11 5x-6y+7z=13
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?