x+2/x²—2x -x-1/x²-4x化简

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x+2/x²—2x-x-1/x²-4x化简x+2/x²—2x-x-1/x²-4x化简x+2/x²—2x-x-1/x²-4x化简(x+2)/(

x+2/x²—2x -x-1/x²-4x化简
x+2/x²—2x -x-1/x²-4x化简

x+2/x²—2x -x-1/x²-4x化简
(x+2)/(x²-2x)-(x-1)/(x²-4x)
=(x+2)/[x(x-2)]-(x-1)/[x(x-4)]
=[(x+2)(x-1)-(x-1)(x-2)]/[x(x-2)(x-4)]
=[(x²+x-2)-(x²-3x+2)]/[x(x-2)(x-4)]
=(x²+x-2-x²+3x-2)/[x(x-2)(x-4)]
=(4x-4)/[x(x-2)(x-4)]
=[2(x-1)]/[x(x-2)(x-4)]
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原式=(x+2)/x(x-2)-(x-1)/(x+2)(x-2)
=[(x+2)²-x(x-1)]/x(x+2)(x-2)
=(x²+4x+4-x²+x)/x(x+2)(x-2)
=(5x+4)/(x³-4x)

手机不行,就这样了,祝愉快