a^3-4ab^2/-a^3-4a^2b-4ab=?2.当x=2,y=3时,求x^2+xy/x^2+2xy+y^2的值十分钟之内给分,

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/17 16:52:39
a^3-4ab^2/-a^3-4a^2b-4ab=?2.当x=2,y=3时,求x^2+xy/x^2+2xy+y^2的值十分钟之内给分,a^3-4ab^2/-a^3-4a^2b-4ab=?2.当x=2,

a^3-4ab^2/-a^3-4a^2b-4ab=?2.当x=2,y=3时,求x^2+xy/x^2+2xy+y^2的值十分钟之内给分,
a^3-4ab^2/-a^3-4a^2b-4ab=?2.当x=2,y=3时,求x^2+xy/x^2+2xy+y^2的值
十分钟之内给分,

a^3-4ab^2/-a^3-4a^2b-4ab=?2.当x=2,y=3时,求x^2+xy/x^2+2xy+y^2的值十分钟之内给分,
(a³-4ab²)/(-a³-4a²b-4ab²)
=[a(a²-4b²)]/[-a(a²+4ab+4b²)]
=-[a(a+2b)(a-2b)]/[a(a+2b)²]
=-(a-2b)/(a+2b)
=(2b-a)/(a+2b)
(x²+xy)/(x²+2xy+y²)
=[x(x+y)]/(x+y)²
=x/(x+y)
=2/(2+3)
=2/5

(1)a^3-4ab^2/-a^3-4a^2b-4ab ^2
=a(a²-4b²)/[-a(a²+4ab+4b²)
=a(a+2b)(a-2b)/[-a(a+2b)²]
=-(a-2b)/(a+2b)

(2)
原式=x(x+y)/(x+y)²
=x/(x+y)
当x=2,y=3时
原式=2/(2+3)=2/5