已知x+y+z=26,2x-y+z=18,求当x-y=1时z的值
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已知x+y+z=26,2x-y+z=18,求当x-y=1时z的值已知x+y+z=26,2x-y+z=18,求当x-y=1时z的值已知x+y+z=26,2x-y+z=18,求当x-y=1时z的值x-y=
已知x+y+z=26,2x-y+z=18,求当x-y=1时z的值
已知x+y+z=26,2x-y+z=18,求当x-y=1时z的值
已知x+y+z=26,2x-y+z=18,求当x-y=1时z的值
x-y=1
x=1+y
代入,则1+y+y+z=26
2(1+y)-y+z=18
所以z=7,x=10,y=9
联立方程组
x+y+z=26
2x-y+z=18
x-y=1
得z=7,y=9,x=10
x=10
z=7
y=9
x=10...y=9....z=7
x+y+z=26 1
2x-y+z=18 2
x-y=1 3
1式减2式,得2y-x=8 4
4式+3式,得y=9
再把y=9代入3式,得x=10
再把y=9、x=10代入1式,得z=7
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