已知2x^2+y^2-2xy-6x+9=0,求x+y-5的值
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已知2x^2+y^2-2xy-6x+9=0,求x+y-5的值已知2x^2+y^2-2xy-6x+9=0,求x+y-5的值已知2x^2+y^2-2xy-6x+9=0,求x+y-5的值2x^2+y^2-2
已知2x^2+y^2-2xy-6x+9=0,求x+y-5的值
已知2x^2+y^2-2xy-6x+9=0,求x+y-5的值
已知2x^2+y^2-2xy-6x+9=0,求x+y-5的值
2x^2+y^2-2xy-6x+9=0,
x²-2xy+y²+x²-6x+9=0
(x-y)²+(x-3)²=0
则:x-y=0,x-3=0
得:x=3,y=3
所以,x+y-5=1
由题意知(x-y)^2+(x-3)^2=0
故有:x=y=3
所以x+y-5=1
原式转化成:(x^2-2xy+y^2)+(x^2-6x+9)=0
(x-y)^2+(x-3)^2=0
求得x=y=3
x+y-5=1
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