已知x y满足x的平方+4xy+4y的平方-x-2y+1\4=0,则x+y的值为?

已知x y满足x的平方+4xy+4y的平方-x-2y+1\4=0,则x+y的值为?
已知x y满足x的平方+4xy+4y的平方-x-2y+1\4=0,则x+y的值为?

已知x y满足x的平方+4xy+4y的平方-x-2y+1\4=0,则x+y的值为?
(x+2y)^2-(x+2y)+(1/2)^2-0
(x+2y-1/2)^2=0
x+2y=1/2
求不出x+y的值

x^2+4xy+4y^2-x-2y+1/4=(x+2y-1/2)^2=0.
则：x+2y-1/2=0
即：x+2y=1/2
x+y=y-1/2

(x+2y)^2-(x+2y)+1/4=0
(x+2y)^2-2x1/2(x+2y)+(1/2)^2=0
(x+2y-1/2)^2=0
x+2y=1/2