llllllllllllllllllllllllllllllllllllllllllllllllll (18 11:40:56)已知函数f(X)=ax+b,若f(0)=1,且f(x+1)=f(x+1)=f(x)+3,求f(x).

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/20 06:18:31
llllllllllllllllllllllllllllllllllllllllllllllllll(1811:40:56)已知函数f(X)=ax+b,若f(0)=1,且f(x+1)=f(x+1)=f

llllllllllllllllllllllllllllllllllllllllllllllllll (18 11:40:56)已知函数f(X)=ax+b,若f(0)=1,且f(x+1)=f(x+1)=f(x)+3,求f(x).
llllllllllllllllllllllllllllllllllllllllllllllllll (18 11:40:56)
已知函数f(X)=ax+b,若f(0)=1,且f(x+1)=f(x+1)=f(x)+3,求f(x).

llllllllllllllllllllllllllllllllllllllllllllllllll (18 11:40:56)已知函数f(X)=ax+b,若f(0)=1,且f(x+1)=f(x+1)=f(x)+3,求f(x).
将f(0)带进去得到b=1 ,则f(x+1)=a(x+1)+1 ,f(x)+3=ax+4
又f(x+1)=f(x)+3,即a(x+1)+1 =ax+4 化简得到a=3
所以f(x)=3x+1

是3x+1吗?