5x^2+2y^2+2xy-14x-10y+17=0,则x=( ),y=( )

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5x^2+2y^2+2xy-14x-10y+17=0,则x=(),y=()5x^2+2y^2+2xy-14x-10y+17=0,则x=(),y=()5x^2+2y^2+2xy-14x-10y+17=0

5x^2+2y^2+2xy-14x-10y+17=0,则x=( ),y=( )
5x^2+2y^2+2xy-14x-10y+17=0,则x=( ),y=( )

5x^2+2y^2+2xy-14x-10y+17=0,则x=( ),y=( )
原式可以化成
(x+y-3)^2 + 4(x-1)^2 + (y-2)^2 = 0
所以x=1,y=2