4(3x+1)²-9=0 x=?

4(3x+1)²-9=0 x=?
4(3x+1)²-9=0 x=?

4(3x+1)²-9=0 x=?
4(3x+1)²-9=0
(3x+1)²=9/4
3x+1=±3/2
3x=-5/2或3x=1/2
x1=-5/6 x2=1/6

4(3x+1)²-9=0
[2(3x+1)+3][2(3x+1)-3]=0
(6x+5)(6x-1)=0
x1=-5/6, x2=1/6

去括号吧！然后化为一元二次方程式就可以解了啊

4(3x+1)²=9
(3x+1)²=9/4
3x+1=±3/2
3x=-1±3/2
故x=-(1/3)±(1/2)=1/6或-5/6