如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点.如果点P在线段BC上以3厘米/秒的 如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点,如果点P在线段BC上以3厘米/秒的速度由B点向C点运动,

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如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点.如果点P在线段BC上以3厘米/秒的如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的

如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点.如果点P在线段BC上以3厘米/秒的 如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点,如果点P在线段BC上以3厘米/秒的速度由B点向C点运动,
如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点.如果点P在线段BC上以3厘米/秒的
如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点,如果点P在线段BC上以3厘米/秒的速度由B点向C点运动,同时,点Q以同样的速度在线段CA上由C点向A点运动.经过几秒后,△BPD与△CQP全等?请说明理由

如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点.如果点P在线段BC上以3厘米/秒的 如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点,如果点P在线段BC上以3厘米/秒的速度由B点向C点运动,
1秒钟.由角B=C角知,要么BD=CP,要么BD=CQ.当BD=CP=5时,BP=CQ=3,三角形全等成立;当BD=CQ=5时,BP=CQ=5,CP=3,CP不等于BP,全等不成立.故仅有BP=3,t=1秒

Christian Louboutin is a name to vouch for in the world of footwear. With the signature red sole, you can certainly enjoy that fabulous sense of uniqueness and the compliments by wearing those Christi...

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如图,已知△ABC中,AB=AC=10CM,BC=8CM,DE平分AB交AC于D,求三角形EBC的周长. 如图,在△ABC中,AB的垂直平分线AC于点D.已知AC=10cm,BD=7cm,求CD的长 如图,在△ABC中,AB的垂直平分线AC于点D.已知AC=10cm,BD=7cm,求CD的长 如图,已知△ABC中,AB=10cm,BC=9cm,AC=17cm,求BC边上的高 如图,已知△ABC中,AB=AC,AB的垂直平分线DE交AB于D,交AC于E,已知△ABC与△EBC的周长分别是26cm、18cm,求AC的长. 如图,在△ABC中,AB=15cm,AC=24cm, 如图,已知△ABC中,AB=6cm,BC=8cm,AC=10cm,D,E,F分别为AB,BC,AC边的中点,求△DEF的周长和面积 如图,在三角形ABC中,AB的垂直平分线交AC于点D,已知AC=10cm,BD=7cm,求CD的长. 如图,在三角形ABC中,AB的垂直平分线交AC于点D已知AC=10CM,BD=7CM求CD的长. 已知:如图,在△ABC中.D是BC上一点,AB=10cm,BD=6cm,AD=8cm,AC=17cm.求△ABC的面积. 如图,已知三角形abc中,ab=ac,ab的垂直平分线交ac于点d,垂足是点e,若ab=10cm,bc=6cm,求△dbc周长 已知:如图,△ABC中,AB=AC,∠C=30°,AD⊥AB,AD=1cm,求证DC,BC,AC的长 如图,已知三角形ABC,AB=AC=10cm,BC=8cm,点D为AB中点. 已知,如图,在△ABC中,AB=AC=20cm,∠ABC=∠ACB=15°,求△ABC的面积 如图,△ABC中,AB=AC=14cm,AB的垂直平分线MN交AC于D,BC=10cm,求△BCD的周长 如图,在△ABC中,AD⊥BC于点D,AB=10cm,AC=17cm,AD=8cm,求△ABC面积, 如图,在△ABC中,AD⊥BC于点D,AB=10cm,AC=17cm,AD=8cm,求△ABC面积. 如图,已知三角形ABC中,AB=13cm,AC=12cm,BC=5cm,求AC边上的中线BD的长?