如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点.如果点P在线段BC上以3厘米/秒的 如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点,如果点P在线段BC上以3厘米/秒的速度由B点向C点运动,
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如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点.如果点P在线段BC上以3厘米/秒的 如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点,如果点P在线段BC上以3厘米/秒的速度由B点向C点运动,
如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点.如果点P在线段BC上以3厘米/秒的
如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点,如果点P在线段BC上以3厘米/秒的速度由B点向C点运动,同时,点Q以同样的速度在线段CA上由C点向A点运动.经过几秒后,△BPD与△CQP全等?请说明理由
如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点.如果点P在线段BC上以3厘米/秒的 如图已知△ABC中,AB=AC=10cm.∠B=∠C,BC=8cm,点D为AB的中点,如果点P在线段BC上以3厘米/秒的速度由B点向C点运动,
1秒钟.由角B=C角知,要么BD=CP,要么BD=CQ.当BD=CP=5时,BP=CQ=3,三角形全等成立;当BD=CQ=5时,BP=CQ=5,CP=3,CP不等于BP,全等不成立.故仅有BP=3,t=1秒
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