(10/x^+3x-4)-(x+1/x-1)+1如题 ..

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(10/x^+3x-4)-(x+1/x-1)+1如题..(10/x^+3x-4)-(x+1/x-1)+1如题..(10/x^+3x-4)-(x+1/x-1)+1如题..=10/(x+4)(x-1)-(

(10/x^+3x-4)-(x+1/x-1)+1如题 ..
(10/x^+3x-4)-(x+1/x-1)+1
如题 ..

(10/x^+3x-4)-(x+1/x-1)+1如题 ..
=10/(x+4)(x-1)-(x+1)(x+4)/(x+4)(x-1)+(x+4)(x-1)/(x+4)(x-1)
=(10-x^2-5x-4+x^2+3x-4)/(x+4)(x-1)
=(-2x+2)/(x+4)(x-1)
=-2(x-1)/(x+4)(x-1)
=-2/(x+4)

*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || (x-1)/(x+3x+2)+6/(2+x-x)-(10-x)/(4-x) X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4) 1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8 好多年没有用过过数学公式了 想不起来怎么算了 想知道 X值是多少 已知x=2π+1求 |x-1|+|x-2|+|x-3|+|x-4|+|x-5|+|x-6|+|x-7|+|x-8|+|x-9|+|x-10| 已知x=2π+1.求(X-1)+(X-2)+(X-3)+(X-4)+(X-5)+(X-6)+(X-7)+(X-8)+(X-9)+(X-10) 1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11=17.7这个方程怎么样求解? (x-1)(x-2)(x-3)(x-4)-(x^2-5x)^2-10(x^2-5x)怎么算? 计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1 如何计算(x-1)(x-2)(x-3)(x-4)-(x^2-5x)^2-10(x^2-5x) X+7/X+1+X+8/X+2-X+9/X+3-X+10/X+4 的解法 x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X x^5-x^4+x^3-x^2+x-1 1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550必须用解方程 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 难倒爱因斯坦的九宫格X 7 X | X 8 1 | X X X |X X X | X 4 X | 7 5 9 |X X 5 | 7 X 9 | X 1 4 |5 X X | X X 8 | 3 9 X |3 9 6 | 4 X 7 | X X 2 |X 8 7 | 9 X X | X X X |4 X X | 6 X 5 | X X X | X X 4 | X X 1 |2 X X | X X X | X X X | X 3 X | X X X |X 6