向CH3COOH溶液中加入CH3COONa溶液,溶液PH变大.有两种解释; (1)CH3COOH电离成CH3COO+H加入CH3COONaCH3COO浓度增大,抑制CH3COOH电离,H浓度变小,PH变大.(2)CH3COONa水解生成NaOH,NaOH与H反应,H浓度降低,PH值变

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向CH3COOH溶液中加入CH3COONa溶液,溶液PH变大.有两种解释;(1)CH3COOH电离成CH3COO+H加入CH3COONaCH3COO浓度增大,抑制CH3COOH电离,H浓度变小,PH变

向CH3COOH溶液中加入CH3COONa溶液,溶液PH变大.有两种解释; (1)CH3COOH电离成CH3COO+H加入CH3COONaCH3COO浓度增大,抑制CH3COOH电离,H浓度变小,PH变大.(2)CH3COONa水解生成NaOH,NaOH与H反应,H浓度降低,PH值变
向CH3COOH溶液中加入CH3COONa溶液,溶液PH变大.有两种解释; (1)CH3COOH电离成CH3COO+H加入CH3COONa
CH3COO浓度增大,抑制CH3COOH电离,H浓度变小,PH变大.
(2)CH3COONa水解生成NaOH,NaOH与H反应,H浓度降低,PH值变大如何证明是(1)而不是(2)

向CH3COOH溶液中加入CH3COONa溶液,溶液PH变大.有两种解释; (1)CH3COOH电离成CH3COO+H加入CH3COONaCH3COO浓度增大,抑制CH3COOH电离,H浓度变小,PH变大.(2)CH3COONa水解生成NaOH,NaOH与H反应,H浓度降低,PH值变
2的解释是说CH3COONa水解生成NaOH的碱性中和了溶液酸性,为了证明它是错的,应该加CH3COONH4溶液,因为该溶液显中性,所以不能中和CH3COOH电离出的氢,而加了CH3COONH4后溶液PH还是变大,就说明是CH3COO-浓度增大,抑制CH3COOH电离,H浓度变小,PH变大.