x^4--4x^3+3x^2+6=0（x的4次方减4倍x的3次方加上3倍x的2次方再加6等于0）

来源：学生作业帮助网编辑：六六作业网时间：2024/12/31 07:36:09

x^4--4x^3+3x^2+6=0（x的4次方减4倍x的3次方加上3倍x的2次方再加6等于0）x^4--4x^3+3x^2+6=0（x的4次方减4倍x的3次方加上3倍x的2次方再加6等于0）x^4-

x^4--4x^3+3x^2+6=0（x的4次方减4倍x的3次方加上3倍x的2次方再加6等于0）
x^4--4x^3+3x^2+6=0（x的4次方减4倍x的3次方加上3倍x的2次方再加6等于0）

x^4--4x^3+3x^2+6=0（x的4次方减4倍x的3次方加上3倍x的2次方再加6等于0）
这个方程貌似没有实数根的.
你看看你的题目有没有写错,如果没有写错的话
我求出的四个虚根是
x=
1+1/2*((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)+1/2*(-(-4*(25+2*i*26^(1/2))^(1/3)*((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)+((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)*(25+2*i*26^(1/2))^(2/3)+9*((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)-4*(25+2*i*26^(1/2))^(1/3))/(25+2*i*26^(1/2))^(1/3)/((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2))^(1/2)
1+1/2*((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)-1/2*(-(-4*(25+2*i*26^(1/2))^(1/3)*((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)+((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)*(25+2*i*26^(1/2))^(2/3)+9*((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)-4*(25+2*i*26^(1/2))^(1/3))/(25+2*i*26^(1/2))^(1/3)/((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2))^(1/2)
1-1/2*((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)+1/2*(-(-4*(25+2*i*26^(1/2))^(1/3)*((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)+((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)*(25+2*i*26^(1/2))^(2/3)+9*((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)+4*(25+2*i*26^(1/2))^(1/3))/(25+2*i*26^(1/2))^(1/3)/((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2))^(1/2)
1-1/2*((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)-1/2*(-(-4*(25+2*i*26^(1/2))^(1/3)*((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)+((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)*(25+2*i*26^(1/2))^(2/3)+9*((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2)+4*(25+2*i*26^(1/2))^(1/3))/(25+2*i*26^(1/2))^(1/3)/((2*(25+2*i*26^(1/2))^(1/3)+(25+2*i*26^(1/2))^(2/3)+9)/(25+2*i*26^(1/2))^(1/3))^(1/2))^(1/2)

*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少? 已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值如果1+x+x^2+x^3=0,求x+x^2+X^3+x^4+x^5+x^6+x^7+x^8的值, 5(x的2次方+X-3)-4x(6+x)+x(-x+4)=0 2x+3x+4x+5x+x+6x+7x=100 x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=? x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002 (x+3x+5x...+2009x)-(2x+4x+6x+...+2010x) 求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 (x-2)(x-4)+4x(x-3)=0 1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8 好多年没有用过过数学公式了想不起来怎么算了想知道 X值是多少已知x=2π+1求 |x-1|+|x-2|+|x-3|+|x-4|+|x-5|+|x-6|+|x-7|+|x-8|+|x-9|+|x-10| 已知x=2π+1.求(X-1)+(X-2)+(X-3)+(X-4)+(X-5)+(X-6)+(X-7)+(X-8)+(X-9)+(X-10) 1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11=17.7这个方程怎么样求解? 4x/(x²-4)-（2x+6)/(x²+x-6)=1-(x-3)/(x²-x-6)