帮帮我!化简sin4a/(1+cos4a)cos2a/(1+cos2a)cosa/(1+cosa)*cos(a/2)/(1+cos(a/2))的过程

来源：学生作业帮助网编辑：六六作业网时间：2024/12/19 18:00:21

帮帮我!化简sin4a/(1+cos4a)*cos2a/(1+cos2a)*cosa/(1+cosa)*cos(a/2)/(1+cos(a/2))的过程帮帮我!化简sin4a/(1+cos4a)*co

帮帮我!化简sin4a/(1+cos4a)*cos2a/(1+cos2a)*cosa/(1+cosa)*cos(a/2)/(1+cos(a/2))的过程
帮帮我!化简sin4a/(1+cos4a)*cos2a/(1+cos2a)*cosa/(1+cosa)*cos(a/2)/(1+cos(a/2))的过程

帮帮我!化简sin4a/(1+cos4a)*cos2a/(1+cos2a)*cosa/(1+cosa)*cos(a/2)/(1+cos(a/2))的过程
sin4a/(1+cos4a)*cos2a/(1+cos2a)*cosa/(1+cosa)*cos(a/2)/(1+cos(a/2))=
2sin2a*cos2a/(2cos2acos2a)*cos2a/(1+cos2a)*cosa/(1+cosa)*cos(a/2)/(1+cos(a/2))=sin2a/(1+cos2a)*cosa/(1+cosa)*cos(a/2)/(1+cos(a/2))=
以同法化简
=sin(a/2)/(1+cos(a/2))=tan(a/4)