函数Y=sin（x+π/3）sin（x+π/2）的最小正周期为?

函数Y=sin（x+π/3）sin（x+π/2）的最小正周期为?
函数Y=sin（x+π/3）sin（x+π/2）的最小正周期为?

函数Y=sin（x+π/3）sin（x+π/2）的最小正周期为?
Y = sin(x+π/3)sin(x+π/2)
= sin(x+π/3)cosx
= 1/2sin(x+π/3+x) + 1/2sin(x+π/3-x) 【积化和差公式】
= 1/2sin(2x+π/3) + 1/2sin(π/3)
最小正周期 = 2π/2 = π

Y=sin（x+π/3）sin（x+π/2）
=1/2*[cos(π/6)-cos(2x+5π/6)]
=-1/2cos(2x+5π/6)+√3/4
最小正周期为T=2π/2=π

y=-1/2(cos(2x+5π/6)-cosπ/60 T=π