设全集U=R,A=:{x-2/x+1＜0},B=:{X|sinx≥根号3/2},则A∩B=?集合A 的取值范围是-1＜x＜2集合B的取值范围是π/3+2kπ≤x≤2π/3+2kπ.A∩B应等于π/3≤x≤2π/3 为什么答案上写着π/3≤x＜2.2是2π啊、应取2π/3 ,为

设全集U=R,A={x|1/x 设全集U=R,集合A={x|0 设全集U=R,集合A={x|0 设全集U=R,A={x|0 设全集U=R,集合A={X|-1 设全集U=R,集合A={x|-1 设全集U=R,集合A={x/1 设全集U=R,A={x|-1 设全集U=R,集合A=(x|-1 设全集U=R,集合A={x|-1 设全集U=R,集合A=（X|-1 设全集U=R,A={x|2 设全集U=R,集合A={x|-2 设全集U=R,A={x|-2 设全集U=R,A{x|2 设全集U=R,A={x|x+1≥0},B={x|x 设全集U=R,A={x|x-1≥0},B={x|1- 设全集U=R,集合A={x｜｜2x-1｜+｜x-2｜