(3m-2n)^+(3m+2n) (3m-2n)-9(m+n)^
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(3m-2n)^+(3m+2n)(3m-2n)-9(m+n)^(3m-2n)^+(3m+2n)(3m-2n)-9(m+n)^(3m-2n)^+(3m+2n)(3m-2n)-9(m+n)^(3m-2n)
(3m-2n)^+(3m+2n) (3m-2n)-9(m+n)^
(3m-2n)^+(3m+2n) (3m-2n)-9(m+n)^
(3m-2n)^+(3m+2n) (3m-2n)-9(m+n)^
(3m-2n)²+(3m+2n) (3m-2n)-9(m+n)²
=(3m-2n)²-9(m+n)²+(3m+2n) (3m-2n)
=(3m-2n+3m+3n)(3m-2n-3m-3n)+9m²-4n²
=-5n(6m+n)+9m²-4n²
=-30mn-5n²+9m²-4n²
=9m²-9n²-30mn
[(m-n)^2*(m-n)^3]^2/(m-n)^4
[(m-n)^2*(m-n)^3]^2/(m-n)^4
3m(m-n)-2n(m-n)的平方
因式分解(n-m)^3(m-n)^2-(m-n)^5
（m-n)2(n-m)3(n-m)4化简
（n-m)^3×(m-n)^2-(m-n)^5
计算(m+n)^3-(n+m)(m-n)^2
(m-n)^3(n-m)^2(m-n)=_____
4m(m-n)^2+4n(n-m)^3
(m-n)3-(2n-m)3
2m-3n-m+2n
(3m-n)(m-2n)=()
(m+2n)(m-3n)
(m-3n)(2m+n)
约分(m-n)^2/(n-m)^3
2(m-n)的2次-(m+n)(m-2n)-3n(n-m)
已知3m=4n,则m/m+n+n/m-n-m^2/m^2-n^2=
m/n=5/3,求（m/m+n）+（m/m+n)-（n^2/m^2-n^2)