(x-2)(x-3)+2(x+y)(x-5)-3(x²-7x+13),其中x=3又3分之1
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(x-2)(x-3)+2(x+y)(x-5)-3(x²-7x+13),其中x=3又3分之1(x-2)(x-3)+2(x+y)(x-5)-3(x²-7x+13),其中x=3又3分之1
(x-2)(x-3)+2(x+y)(x-5)-3(x²-7x+13),其中x=3又3分之1
(x-2)(x-3)+2(x+y)(x-5)-3(x²-7x+13),其中x=3又3分之1
(x-2)(x-3)+2(x+y)(x-5)-3(x²-7x+13),其中x=3又3分之1
求什么呀
中间的x+y是不是有问题两个未知数怎么算啊
这不是方程啊
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