2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.5,求教啊= =2x+3y/2+3x+2y/5=11/3 ,3(2x+3y)/2=6(3x+2y)/7+2.5

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2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.5,求教啊==2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.52x

2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.5,求教啊= =2x+3y/2+3x+2y/5=11/3 ,3(2x+3y)/2=6(3x+2y)/7+2.5
2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.5,求教啊= =
2x+3y/2+3x+2y/5=11/3 ,3(2x+3y)/2=6(3x+2y)/7+2.5

2x+3y/2+3x+2y/5=11/3,3(2x+3y)/2=6(3x+2y)/7+2.5,求教啊= =2x+3y/2+3x+2y/5=11/3 ,3(2x+3y)/2=6(3x+2y)/7+2.5
题目中第一式是不是应该是:(2x+3y)/2+(3x+2y)/5=11/3 , 否则这样出没意义.
如果是这样的话,解法如下:
15(2x+3y)+6(3x+2y)=110, 21(2x+3y)-12(3x+2y)=35
48x+57y=110,6x+39y=35
加减法解得:x=3/2, y=2/3