(x1-x2)+(x2-x1)/x1x2 = (x1-x2)(1- 1/x1x2) 请问这是怎么变形的?
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(x1-x2)+(x2-x1)/x1x2=(x1-x2)(1-1/x1x2)请问这是怎么变形的?(x1-x2)+(x2-x1)/x1x2=(x1-x2)(1-1/x1x2)请问这是怎么变形的?(x1-
(x1-x2)+(x2-x1)/x1x2 = (x1-x2)(1- 1/x1x2) 请问这是怎么变形的?
(x1-x2)+(x2-x1)/x1x2 = (x1-x2)(1- 1/x1x2)
请问这是怎么变形的?
(x1-x2)+(x2-x1)/x1x2 = (x1-x2)(1- 1/x1x2) 请问这是怎么变形的?
提取公因式(x1-x2)
(x1-x2)+(x2-X1)/x1x2=(x1-x2)-(x1-x2)/x1x2,提取公因式(x1-x2)得出(x1-x2)(1-1/x1x2)
(x1-x2)-(x1-x2)/x1x2 = (x1-x2)(1- 1/x1x2)
1 - 1/x1x2 = 1-1/x1x2
x1-x2)+x1x2分之4(x2-x1)怎样化简成((x1-x2)(1-x1x2分之4)
(X2-X1)-[(X2-X1)/(X1X2)]是怎样得到(X2-X1)(1-1/X1X2)
求化简过程,(x1+a/x1)-(x2+a/x2)=(x1-x2)/x1x2(x1x2-a)
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(x1x2²+x1²x2-x1+x2)/x1x2怎么分解因式?
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两数平方的差用X1+X2 X1*X2比如X1²+X2²可以写成 (X1+X2)²-2X1X2 那么X1²-X2² 呢X1 X2 是一元二次方程的2个跟!
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