(0.5x^5y^2-4分之3x^4y^5-12分之1x^3y^2)/(-4分之1x^3y^2)[(2xy-3)(2xy+3)+(xy+3)^2]/xy
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(0.5x^5y^2-4分之3x^4y^5-12分之1x^3y^2)/(-4分之1x^3y^2)[(2xy-3)(2xy+3)+(xy+3)^2]/xy(0.5x^5y^2-4分之3x^4y^5-12
(0.5x^5y^2-4分之3x^4y^5-12分之1x^3y^2)/(-4分之1x^3y^2)[(2xy-3)(2xy+3)+(xy+3)^2]/xy
(0.5x^5y^2-4分之3x^4y^5-12分之1x^3y^2)/(-4分之1x^3y^2)
[(2xy-3)(2xy+3)+(xy+3)^2]/xy
(0.5x^5y^2-4分之3x^4y^5-12分之1x^3y^2)/(-4分之1x^3y^2)[(2xy-3)(2xy+3)+(xy+3)^2]/xy
(0.5x^5y^2-4分之3x^4y^5-12分之1x^3y^2)/(-4分之1x^3y^2)
=0.5x^5y^2/(-4分之1x^3y^2)-4分之3x^4y^5/(-4分之1x^3y^2)-12分之1x^3y^2/(-4分之1x^3y^2)
=-2x^2+3xy^3+3分之1
[(2xy-3)(2xy+3)+(xy+3)^2]/xy
=(4x²y²-9+x²y²+6xy+9)/xy
=(5x²y²+6xy)/xy
=5xy+6
2分之x+y+3分之x-y;4(x+y)-(x-y)谢谢了,
解方程组2分之x+y+3分之x-y=6 4(x+y)-5(x-y)=2
{x分之2-y分之3=4,x分之3+y分之6=5
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4分之3x+2y=5分之2x+y=6分之x-y+1的解法.
2分之x+y=5分之3x+4y,2分之x+y=1
4分之3x+2y等于5分之2x+y等于6分之x-y+1
设2x分之3x-5y=4 则y分之x=
已知2分之x+1=4分之y+3+5分之x+y求x+2y+3分之3x+2y+1
已知3分之x+1=4分之y+3=5分之x+y,则x+2y+3分之3x+2y+1得多少?