解分式方程1/x-1+x²+1 1 1----- = ----- x-1 x²-1

解分式方程1/x-1+x²+1 1 1----- = ----- x-1 x²-1
解分式方程1/x-1+x²+1

  1         1

----- = ----- 

x-1       x²-1

解分式方程1/x-1+x²+1 1 1----- = ----- x-1 x²-1
1/(x-1) = 1/(x²-1)
两边同时乘以 x²-1,得 x+1 = 1,即 x = 0
经检验,x =0 是原分式方程的解
1/(x-2) +3 = (x-1) /(x+1)
两边同时乘以 (x-2)(x+1),得 x+1+3(x-2)(x+1) = (x-2)(x-1)
即 x+1+3x²-3x-6 = x²-3x+2
整理,得 2x²+x-7 =0
解得 x = (-1±√57)/4
经检验,x = (-1±√57)/4 是原分式方程的解
(2-x)/(3+x) = 1/2 +1/(x+3)
方程两边同时乘以 2(x+3),得 4-2x = x+3 + 2
解之,得 x = -1/3
经检验,x = 1/3 是原分式方程的解
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