X^4-3X^2-7/4
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X^4-3X^2-7/4X^4-3X^2-7/4X^4-3X^2-7/4用换元法求解令x=t(t>0)则原方程化为t-3t-7/4=0用求根公式得t1=7/2,t2=-1/2因为t=x>0所以t=7/
X^4-3X^2-7/4
X^4-3X^2-7/4
X^4-3X^2-7/4
用换元法求解 令x=t(t>0) 则原方程化为t-3t-7/4=0 用求根公式得t1=7/2 ,t2=-1/2 因为t=x>0 所以t=7/2 即x=7/2 解得x=±7√2/2
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