化简:5/(x²-5x-4) +4/(x²-5x-6) -8/(x²-10x+24)
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/11 21:10:49
化简:5/(x²-5x-4)+4/(x²-5x-6)-8/(x²-10x+24)化简:5/(x²-5x-4)+4/(x²-5x-6)-8/(x
化简:5/(x²-5x-4) +4/(x²-5x-6) -8/(x²-10x+24)
化简:5/(x²-5x-4) +4/(x²-5x-6) -8/(x²-10x+24)
化简:5/(x²-5x-4) +4/(x²-5x-6) -8/(x²-10x+24)
感觉应该是5/(x²-5x+4),不然也太复杂了
5/(x²-5x+4) +4/(x²-5x-6) -8/(x²-10x+24)
=5/[(x+1)(x-4)]+4/[(x+1)(x-6)]-8/[(x-6)(x-4)]
=[5(x-6)+4(x-4)-8(x+1)]/[(x+1)(x-4)(x-6)]
=(5x-30+4x-16-8x-8)/[(x+1)(x-4)(x-6)]
=(x-54)/[(x+1)(x-4)(x-6)]
如果原题真的是5/(x²-5x-4)那就只能通分了.你可以试试
把分母因式分解,再同分计算
你题目有没有错?
你确定题目没有符号或数字抄错吧?
你要是做出来了,可以把答案发给我吗?原式==5/[(x+1)(x-4)]+4/[(x+1)(x-6)]-8/[(x-6)(x-4)]
=[5(x-6)+4(x-4)-8(x+1)]/[(x+1)(x-4)(x-6)]
=(5x-30+4x-16-8x-8)/[(x+1)(x-4)(x-6)]
=(x-54)/[(x+1)(x-4)(...
全部展开
你确定题目没有符号或数字抄错吧?
你要是做出来了,可以把答案发给我吗?
收起