若x-y=6,y-z=5,求x²+y²+z²-xy-xz-yz的值.计算题:1.19.8²-39.6×40.2+40.2²2.(2分之1a-3b)(3b-2分之1a)

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若x-y=6,y-z=5,求x²+y²+z²-xy-xz-yz的值.计算题:1.19.8²-39.6×40.2+40.2²2.(2分之1a-3b)(3

若x-y=6,y-z=5,求x²+y²+z²-xy-xz-yz的值.计算题:1.19.8²-39.6×40.2+40.2²2.(2分之1a-3b)(3b-2分之1a)
若x-y=6,y-z=5,求x²+y²+z²-xy-xz-yz的值.
计算题:
1.19.8²-39.6×40.2+40.2²
2.(2分之1a-3b)(3b-2分之1a)

若x-y=6,y-z=5,求x²+y²+z²-xy-xz-yz的值.计算题:1.19.8²-39.6×40.2+40.2²2.(2分之1a-3b)(3b-2分之1a)
x-y=6
y-z=5
两式相加:
x-z=11
x²+y²+z²-xy-xz-yz
=2(x²+y²+z²-xy-xz-yz)÷2
=(2x²+2y²+2z²-2xy-2xz-2yz)÷2
=(x²-2xy+y²x²-2xz+z²+y²-2yz+z²)÷2
=[(x-y)²+(x-z)²+(y-z)²]÷2
=(36+121+25)÷2
=91

x-y=6①
y-z=5②
①+②得:
x-z=11
x²+y²+z²-xy-xz-yz
=2(x²+y²+z²-xy-xz-yz)/2
=(2x²+2y²+2z²-2xy-2xz-2yz)/2
=(x-y)²+(x-z)&su...

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x-y=6①
y-z=5②
①+②得:
x-z=11
x²+y²+z²-xy-xz-yz
=2(x²+y²+z²-xy-xz-yz)/2
=(2x²+2y²+2z²-2xy-2xz-2yz)/2
=(x-y)²+(x-z)²+(y-z)²/÷2
=(36+121+25)/2
= 91
19.8²-39.6×40.2+40.2²
=382.04-1591.82+1616.04
=416.16
(2分之1a-3b)(3b-2分之1a)
=- 9/4

收起

x=6+y, z=y - 5,代进去就可以了,最后有y 的项正好全部约去,等于 91 。

计算题1:19.8²-39.6×40.2+40.2²
19.8²-39.6×40.2+40.2²=(19.8+40.2)²=3600