求和:1/1*4 + 1/4*7 +.+1/(3n-2)(3n+1),怎么算?

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求和:1/1*4+1/4*7+.+1/(3n-2)(3n+1),怎么算?求和:1/1*4+1/4*7+.+1/(3n-2)(3n+1),怎么算?求和:1/1*4+1/4*7+.+1/(3n-2)(3n

求和:1/1*4 + 1/4*7 +.+1/(3n-2)(3n+1),怎么算?
求和:1/1*4 + 1/4*7 +.+1/(3n-2)(3n+1),怎么算?

求和:1/1*4 + 1/4*7 +.+1/(3n-2)(3n+1),怎么算?
把通项化为[1/(3n-2)-1/(3n+1)]/3
整个提出个1/3(1-1/4+1/4-1/7+.+1/(3n-5)-1/(3n+2)+1/(3n+2)-1/(3n+1)
化简为1/3[1-1/(3n+1)]