已知X^2-6x+|y+1|=0,求(x+2y)^2(x-2y)^2-(x+2y)(x^2+4y^2)(x+2y)的值

已知X^2-6x+|y+1|=0,求(x+2y)^2(x-2y)^2-(x+2y)(x^2+4y^2)(x+2y)的值
已知X^2-6x+|y+1|=0,求(x+2y)^2(x-2y)^2-(x+2y)(x^2+4y^2)(x+2y)的值

已知X^2-6x+|y+1|=0,求(x+2y)^2(x-2y)^2-(x+2y)(x^2+4y^2)(x+2y)的值

题目不对吧！应该是X^2-6x+9+|y+1|=0吧 后面是(x+2y)^2(x-2y)^2-(x+2y)(x^2+4y^2)(x-2y)吧
因为X^2-6x+9+|y+1|=0,
即（x-3)^2+|y+1|=0,
所以x-3=0,y+1=0
所以x=3,y=-1
(x+2y)^2(x-2y)^2-(x+2y)(x^2+4y^2)(x-2y) <...

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题目不对吧！应该是X^2-6x+9+|y+1|=0吧 后面是(x+2y)^2(x-2y)^2-(x+2y)(x^2+4y^2)(x-2y)吧
因为X^2-6x+9+|y+1|=0,
即（x-3)^2+|y+1|=0,
所以x-3=0,y+1=0
所以x=3,y=-1
(x+2y)^2(x-2y)^2-(x+2y)(x^2+4y^2)(x-2y)
=[(x+2y)*(x-2y)]^2-(x+2y)(x+2y)(x^2+4y^2)
=(x^2-4y^2)^2-(x^2-4y^2)(x^2+4y^2)
=(x^2-4y^2)[(x^2-4y^2)-(x^2+4y^2)]
=(x^2+4y^2)（-4y^2)
=(9+4)(-4)
=13*（-4）
=-52
若我认为的不对，就追问吧

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