(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?
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(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?(1+2sinxcosx+cos^2x
(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?
(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?
(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?
解由(1+2sinxcosx+cos^2x-sin^2x)+1
=(cos^2x+sin^2x+2sinxcosx+cos^2x-sin^2x)+1
=(cos^2x+2sinxcosx+sin^2x+cos^2x-sin^2x)+1
=[(cosx+sinx)²+cos^2x-sin^2x]+1
=[(cosx+sinx)²+（cosx-sinx）（cosx+sinx）]+1
=[(cosx+sinx)（cosx+sinx+cosx-sinx）]+1
化简2*(sinxcosx-cos平方x)+1
sin^2xtanx+(cos^2x/tanx)+2sinxcosx-1+cos/sinxcosx
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2sin^2x-sinxcosx-cos^2=1
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化简1+2sinxcosx+2cos²x
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cos^2+2sinxcosx+sin^2x
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y=sinxcosx+cos(2x)化简
化简:(cos*2x-0.5)/(sinxcosx)
sin^2xtanx+cos^2x/tanx+2sinxcosx-(1+cosx/sinxcosx)化简
已知tanx=2,则(1)1/4sin方x-3sinxcosx/cos方x+2sinxcosx
tanx=2,则1/4sin²x-3sinxcosx/cos²x+2sinxcosx=多少
y=(cos^2x)/(sinxcosx-sin^2x),(0
sin²X-sinxcosx+2cos²x=化简
化简f(x)=cos^2(x+π/12)+sinxcosx