A={(x,y)|y=x²-1}B={(x,y)|x-y-1=0}求A∩B

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A={(x,y)|y=x²-1}B={(x,y)|x-y-1=0}求A∩BA={(x,y)|y=x²-1}B={(x,y)|x-y-1=0}求A∩BA={(x,y)|y=x

A={(x,y)|y=x²-1}B={(x,y)|x-y-1=0}求A∩B
A={(x,y)|y=x²-1}B={(x,y)|x-y-1=0}求A∩B

A={(x,y)|y=x²-1}B={(x,y)|x-y-1=0}求A∩B
0 和1