3x=5y 2x=7z x-2y+3z=4 求解三元一次方程组.

x/2=y/3=z/5 x+3y-z/x-3y+z 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX.. {x+y+z=1;x+3y+7z=-1;z+5y+8z=-2 若X:Y:Z=5:6:7那么(Y-X):(Y+Z)和(X+2Y+3Z):(3X+2Y+Z) x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2 x+y-z=3 y+z-x=5 z+x-y=7 求x,y,z 证明 ：x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0 (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? 3x-y=-7,y+2z=2,2x-2z=-5 求x,y,z x+y+z=0,3x-2y-2z=5,y-z=2x-7 X-Y-Z=0 X+Y-3Z=4 2X-5Y+7Z=21 2x+5y+4z=6,3x+y-7z=-4,x+y-z=? 3x+7y+4z=35,x+5y+2z=40,x+y+z=( ) {x+y+z=1 {x+3y+7z=-1 {x+5y+8z=2 {x+y+z=1 {x+3y+7z=2 {x+5y+19z=4 已知2x+5y+4z=6 3x+y-7z=-4求x+y-z