(x-3)^2+(√ X^2-6X+16)=13
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(x-3)^2+(√X^2-6X+16)=13(x-3)^2+(√X^2-6X+16)=13(x-3)^2+(√X^2-6X+16)=13设(x-3)^2=yy+√(y+7)=13y+7=169-26
(x-3)^2+(√ X^2-6X+16)=13
(x-3)^2+(√ X^2-6X+16)=13
(x-3)^2+(√ X^2-6X+16)=13
设(x-3)^2=y
y+√ (y+7)=13
y+7=169-26y+y^2
y^2-27y+162=0
y=9或18(舍去)
所以x=0或6
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