已知a> 0,函数f(x)=-2asin(2x+ π/6)+2a+b,当x∈[0,π/2]时,-5≤ f(x)≤ 1.求f(x)的单调区间?
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/29 00:39:46
已知a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当x∈[0,π/2]时,-5≤f(x)≤1.求f(x)的单调区间?已知a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当
已知a> 0,函数f(x)=-2asin(2x+ π/6)+2a+b,当x∈[0,π/2]时,-5≤ f(x)≤ 1.求f(x)的单调区间?
已知a> 0,函数f(x)=-2asin(2x+ π/6)+2a+b,当x∈[0,π/2]时,-5≤ f(x)≤ 1.求f(x)的单调区间?
已知a> 0,函数f(x)=-2asin(2x+ π/6)+2a+b,当x∈[0,π/2]时,-5≤ f(x)≤ 1.求f(x)的单调区间?
sin(2x+ π/6)的单调区间是在x∈[0, π/6]为增,在x∈[π/6, π/2]为减,
因为系数-2a小于零,所以f(x)在x∈[0, π/6]为减,在x∈[π/6, π/2]为增
已知函数f(x)=Asin(x+&)(A>0,0
已知函数f(x)=Asin(2x+φ) (A>0,0已知函数f(x)=Asin(2x+φ) (A>0,0
已知函数f(x)=Asin(ωx+a)(A>0,ω>0,-π/2
已知函数f(x)=Asin(2x+a)(A>0,0
急用::已知函数f(x)=Asin^2(ωx+φ)(A>0,0
已知函数f(x)=Asin(2x+φ) (A>0,0
已知函数f(x)=Asin(2x+b)(A>0,0
已知函数f(x)=Asin(2x+φ) (A>0,0
已知函数f（x）=Asin（2x+φ）（A>0,0
已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,-π/2
已知函数f(x)=Asin(2x+B) (A>0 0
已知函数f(x)=Asin(x/2+φ)(A>0,0＜φ
三角函数题 很紧急已知函数f(x)=Asin(2x+φ)（A>0,0
已知函数f(x)=Asin^2 (wx+a),A>0,w>0,0
已知函数f(x)=Asin(wx+a)(A>0,w>0,-π/2
已知函数f(x)=Asin^2(wx+fai)(A>0,w>0,0
已知函数f(x)=Asin(wx+φ)(其中A>0,w>0,-π/2
已知函数f(x)=Asin(wx+α)(A>0,w>0,-π/2